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Question 1 of 4
1. Question
2 points
When $a \ne 0$, there are two solutions to \(ax^2 + bx + c = 0\) and they are
$$x = {-b \pm \sqrt{b^2-4ac} \over 2a}.$$
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Question 2 of 4
2. Question
1 points
On which date is JEE Advanced scheduled to happen ?
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Hint
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Question 3 of 4
3. Question
1 points
JEE Advanced 2020 exam would be conducted for admission to how may IITs ?
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Question 4 of 4
4. Question
1 points
Who organised the JEE advanced for 2019 ?
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