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CBSE Class 9 Maths Circles (Hard)
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The radius of a circle is 13 cm and the length of one of its chords is 10 cm. The distance of the chord from the centre is
A chord is at a distance of 8 cm from the centre of a circle of radius 17 cm. The length of the chord is
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\text { In the given figure, } B O C \text { is a diameter of a circle and } A B=A C \text { . Then, } \angle A B C=
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\text { In the given figure, } O \text { is the centre of a circle. If } \angle O A B=40^{\circ} \text { and } C \text { is a point on the circle, then } \angle A C B=
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\mathrm{AB} \text { and } \mathrm{CD} \text { are two equal chords of a circle with centre } \mathrm{O} \text { such that } \angle \mathrm{AOB}=80^{\circ} \text { , then } \angle \mathrm{COD}=
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An equilateral triangle of side 9 cm is inscribed a circle. The radius of the circle is
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\text { In figure, } \triangle \mathrm{ABC} \text { is an equilateral triangle and } \mathrm{ABDC} \text { is a quadrilateral then } \angle \mathrm{BDC}=
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\text { In the given figure, } O \text { is the centre of a circle. If } \angle A O B==100^{\circ} \text { and } \angle A O C=90^{\circ} \text { , then } \angle B A C=
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\begin{aligned}
&\text { In the given figure, } A B \text { is a chord of a circle with centre } O \text { and } B O C \text { is a diameter. If } O D \perp A B \text { such that } O D=6\\
&\mathrm{cm} \text { , then } \mathrm{AC}=
\end{aligned}
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